we are
finding the amount of the sample undecayed after 24 days.
Iodine-131
has a half life of 8 days 28 minutes and 48 seconds,
But we can
ignore the 8 minutes and the seconds sine it is not up to a day.
Therefore let us observe it this way
Half life is
the time taken for half of the mass of a sample to disappear,
Given that
iodine has a half life T1/2 = 8
days.
let us observe it in this way, after one half-life
elapse 50% percent of its mass is given off, and 50% of
the mass is left and it takes 8 days . After another half-life, ½ of the remaining 50 percent is also gone ,
we are left with only 25 percent of the original
mass and this after 16 days.
After two
half-life 75% mass is lost we are left with 25% and it takes 16 days( 16 days) .
Therefore after another half-life ½ of the remaining 25% which is 12.5% percent of the original mass is left and it will
take 24 days( 16+8 days).
Therefore after
3 half life 75% + 12% =87.5% is lost and only 12.5% remains ,
Each half
takes 8 days
there 3 * 8 = 24days
in a tabular form we can have
|
S/n
|
Number of half-life
|
Amount remaining
|
Amount decayed
|
Total
|
Number of days
|
|
1
|
One
|
50%
|
50%
|
100%
|
8 days
|
|
2
|
Two
|
25%
|
75%
|
100%
|
16 days
|
|
3
|
Three
|
12.5%
|
87.5%
|
100%
|
24. days
|
Therefore after
24 days, 12.5 % is left.
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