if am iodine has a halflife
of 8, in 24 days it will decays
24/8 = 3 times.
Therefore after every decay
half of the available mass is lost by 50%
we are finding
the amount of the sample decayed after 24 days.
Iodine-131
has a half life of 8 days 28 minutes and 48 seconds,
But we can
ignore the 8 minutes and the seconds sine it is not up to a day.
Therefore let us observe it this way
Half life is
the time taken for half of the mass of a sample to disappear,
Given that
iodine has a half life T1/2 = 8
days.
let us observe it in this way, after one half-life
elapse 50% percent of its mass is given off, and 50% of
the mass is left and it takes 8 days . After another half-life, ½ of the remaining 50 percent is also gone ,
we are left with only 25 percent of the original
mass and this after 16 days.
After two
half-life 75% mass is lost we are left with 25% and it takes 16 days( 16 days) .
Therefore after another half-life ½ of the remaining 25% which is 12.5% percent of the original mass is left and it will
take 24 days( 16+8 days).
Therefore after
3 half life 75% + 12% =87.5% is lost and only 12.5% remains ,
Each halflife
takes 8 days
there 3 * 8 = 24days
therefore after 24 days only 12.5% is left undecayed
therefore 12.5% of 1000mg is
=125mg
Is what will will
remain
No comments:
Post a Comment