to remove to protons from a sulfur atom, is
like sying the sulfur atom has undergone an alpha decay,
let us
put the equation fast
32S → 42H + 28Si
therefore from the alpha decay equation the
nuclide formed will be silicon-28
the atomic number of the sulphur( parent
nuclide has decreased by two while the mass number has decreased by four.
No comments:
Post a Comment