a nuclide undergoes β decay and forms 110i. what is the nuclide?

when a nuclide  undergoes a beta decay to form iodine-110, the parent nuclide must have an atomic number less than the daughter nuclide by one while the mass number remain the same. in a beta decay the number of protons increases by one while the number of neutrons decreases by one, the nuclide formed is xenon-110

as shown in  the equation below

¹¹⁰₅₃I → ¹¹⁰₅₄Xe + ⁰_-1e