what particle is emitted in the following radioactive decay? 2714si→2713al.




 let us put down the equation fast
2714Si→2713Al  + X
In the above reaction, the  atomic mass remain unchained this signifies a beta emission or positron emission while the nuclear charges decreases by one , this signifies a beta plus a positron emission, therefore the above equation should be written as
2714Si→2713Al + 0+1e
That when silicon-27 emits a positron, alluminium-27 is formed.
Let us balance the equation to check if we are wrong,
The law of conservation of matter in nuclear reaction requires that the total mass on the product side must be equal to the total mass on the reactant side and the  toal charge on the reactant side must be equal to the total charge on the product side
Therefore  
Total mass on the left hand side is 27 and total mass on the right hand side is 27 +0= 27
 Total charge on the left hand side is 14 and likewise the total charge on the reactant side is  13+1= 14
 Therefore te equation is balanced and we are not wrong

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