When radon decays by alpha decay, an atom with atomic
number less than two and a mass number less than 4 is created , how? What happen
is that when an alpha particle decays, the atom emits a particle with two
protons and two neutron, a helium nuclei like particle. The atom forme is two position below
radon n the periodic table of elements. And the atom that fit this description is polonium-218
Let us write down the
equation
22286Rn → 21884Po
+ 42He + energy
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