how many moles of co are contained in a 5.00 l tank at 155°c and 2.80 atm?



answer this question
PV =nRT
WHERE R =8.314
P=2.80 atm =283710
V =5.00L=0.005m3
T=155+273 =428k
n= PV/RT

n = (283710×0.005)/(8.314 ×428)

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