identify the product of radioactive decay and classify the given nuclear reactions accordingly.

·       ²³⁷₉₃Np→⁴₂He + ?

 the decay equation is therefore ²³⁷₉₃Np→⁴₂He + ²³³₉₁Pa

 and the product is protactinium

·       _____→²³³₉₂U + ⁰₋₁e

and the decay equation is

¹³⁵₆₀Nd → ¹³⁵₅₉Pa ⁰₊₁e

 the resulting atom is praseodymium-135.