7535br→_____+0+1e, complete this equation

let me rewrite this equation

⁷⁵₃₅Br→_____ + ⁰₊₁e

 the above decay is a positron emission, this kind of decay reduces atomic number  by one while the atomic mass remain unchanged.

⁷⁵₃₅Br→ ⁷⁵₃₄Se+ ⁰₊₁e

 the resulting atom is selenium-75.