13560nd→_____+0+1e, complete this equation




let me rewrite the equation again
13560Nd→_____+ 0+1e
 THE ABOVE IS A POSITRON EMISSION, in this type of decay, the atomic number decreases while the atomic mass remain the same, therefore the  the balance equation is
13560Nd → 13559Pa 0+1e
 the resulting atom is praseodymium-135.

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