calculating the binding energy for hydrogen isotopes

calculating the binding energy for  the binding energy on the three isotopes of hydrogen

hydrogen atom  three isotopes, the proton, deuterium and tritium.

 the hydrogen has a  measured mass of 1.007825, the 1^st isotopes of hydrogen as only a proton, it binding energy can be said to be zero.

 the  binding energy fir the next isotope of hydrogen deuterium D, this  isotopes has a proton and a neutron,

 therefore the calculated mass will be

P(1.007825) + N(1.008665)= calculated mass.

1(1.007825) + 1(1.008665)= 2.01649

BUT THE MEASURED MASS is 2.014102

therefore the mass defects is    =   2.01649 -2.014102=0.002388

binding energy E =∆MC²

0.002388X (3 X 10⁸)² m/s

2.14920 x 10⁸ MeV

to obtain the binding energy per nucleon , we divide the binding energy by the number of nucleons which is 2

we have 1.0746 x 10⁸ MeV

to calculate the binding energy for tritium, we obtain

 the calculated mass as follows

(1.007825) + 2(1.008665)= 3.02516

while the measured mass is 3.016049

, thus  the mass defect is equal to 0.009111

 the binding energy is given as

E =∆MC²

0.009111 x (3 X 10⁸)² m/s

8.19990x 10⁸ MeV

Binding energy per nucleon will be given by  4.5555x 10⁷ MeV