in this 235 92u+10n→azsr+143 54xe+310n find the the atomic and mass number for this reaction?

let me rewrite the equation ²³⁵ ₉₂U+¹₀n→^A_ZSr+¹⁴³₅₄Xe+³¹₀n

the mass and charge must be balanced

for the masses 235 + 1 →  A + 143 + 3

236 →  A + 147

A → 236-147 →  89

the nuclear charge is  therefore

92 → z +54

z → 92-54→ 38

 therefore the atomic number correspond to strontium and the isotope is strontium-89